Option 1 : 192

**Concept:**

Permutaion = \(\frac{n!}{(n - r)!}\)

**Calculation:**

⇒ Given digits are 0, 1, 2, 5, 6, 8.

⇒ Consider five blank = _ _ _ _ _

⇒ The number formed is an odd number.

⇒ The unit place can be filled with only 1 or 5 i.e. in 2 ways.

⇒ The number can not begin with '0' Hence first place can be filled in 4 ways.

⇒ The remaining three blanks can be filled with 4 digits in ^{4}P_{3} ways.

⇒ The total number of 5-digit odd numbers = 2 × 4 × ^{4}P_{3} = 192

**∴ The required result will be 192.**